81x^2+117x+40=0

Solution for 81x^2+117x+40=0 equation:

81x^2+117x+40=0

a = 81; b = 117; c = +40;
Δ = b2-4ac
Δ = 1172-4·81·40
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(117)-27}{2*81}=\frac{-144}{162}
=-8/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(117)+27}{2*81}=\frac{-90}{162}
=-5/9
$